I decided to give the crime scene dates and mailed letter/card dates a value in numbers and in letters of the the alphabet. I figured it was a long shot to see if Zodiac was calculating using dates to create the alphabet is some way or to preplot his crimes. Was it possible each date was inportant to build an alphabet of secret letters and numbers? I figured if I did all the crime scenes and the mailed letters, I would get lucky and hit at least half of the alphabet. I think the odds for getting that many are probably astronomical since there were only 27 dates to convert, but I thought it was worth the last 13 hours to do the work I have done here. The results are fantastic. I hit 23 of 26 letters of the alphabet when I did every date twice. Let me explain what twice means:
Since Zodiac was (maybe still is?) into pairs and symetry, I decided to use the 2 digit,2 digit,4 digit date and the same date as a 2 didgit,2didgit,2 didgit date (2 conversions to numbers and letters of the alphabet) Example:
02.14.1974 (2 digit,2 digit,4 digit =) 2+1+4+1+9+7+4= 28. since 28 is higher than 26(possible letter count of the alphabet) I broke it again to get 2+8=10. This became the letter J and since 10 breaks again, it gets a second number of 1+0=1 or A,thus in the 2-2-4 digit sequence, this date gets the letters A(1) and J(10) applied to that date. then 02.14.74 (2 digit, 2 digit, 2 digit) gets converted as well in an alternate conversion(2-2-2 didgit sequence) that is 2+1+4+7+4= 18 or 1+8=9 R(18) and I (9)
taking all of the dates I came up with 22 hidden letters of 26 of the alphabet in 27 documented dates. I believe this is something big.
What it means is this:
There is a date or two missing, I suspect it is 2 dates to make the #'s that convert to crime dates that ,with all of the letters, made up the full alphabet and thus, are probably in some way(if the whole alphabet is complete) linked to the way the unsolved cyphers can be interpreted. I know it was a long shot, but now it can be recorded and used. I wonder if anyone ever took the time to do this?
I am missing the converted values of 3 alphabetic letters. The letters are L,N, and V. This means I need to find the crime that was not concidered to be Zodiacs that really is his crime, or the possible 2 crimes I should say. This will be my next task, to find the missing crime(s) date(s) that completes this alphabet. It may also be the 1981 letter, but I havent found it yet. It could also be an earlier nightstalker crime or possibly one of the crimes where he left a match(reference to pairs).
Also I suspect a hidden Baconian cypher and will work it next and explain it as well. for now, here are my results:
Without showing all of the math(since it would take a while to post it all), I gave an example so you can test my conversions, but I simplified it here for you and just gave the final numer and letter value of each date: Do you notice all the pairs and similar results that were found? Only a mathmatician could have calcilated these dates to match like that. This is no coincidence, it was calculated. (MHO)
Crimes are marked with a letter and mailed letters are assigned by number and iin order. I put the crime dates and letters together. Here they are
The digit sequence results of each date is as such as presented. The 2-2-4 sequence results(shown first) and a dash dividing the 2-2-2 sequence (which is shown second).
Example using first Date:
A) 10. 30 1966 / 10.30.66
1+3+1+9+6+6/ or 1+3+6+6
=26 or (2+6=8)/ =16 or (1+6=7)
26 =(Z) 8= (H)/ ~ 16 =P 7 =G
A) 10.30.1966 CRIME Cherri Jo Bates .....*.Values:26=Z 8=H ..~ 16=P.. 7=G
1) 11-29-1966 Mailed Letter *Values 26=Z 8=H ~ 16-P 7=G
2) 04.30.1967 Mailed Letter %Values 3=C ~ 20=T 2=B
B) 12.20.1968 Crime David F and Betty Lou J 11= K ~ 19=S 10=J 1=A
3) 04.31.1969 Mailed Letter Values 6 =G ~ 26=Z 8=H
C) )7.)4.1969 Crime Darlene Ferrin Mike Mageau $$Values 9=I ~ 26=Z 8=H
4) 08.04.1966 Mailed Letter Values 8=H ~ 24=X 6=F
D) 09.27.69 Crime Bryan Hartnell Cecilia Shepard Values 7=G ~ 6=F
E) 10.11.1969 Crime Paul Stine $Values 10=J 1=A ~ 18=R 9=I
5) 10.13.1969 Mailed Letter %Values 3=C ~ 20 =T 2=B
6) Mailed Letter $$$Values 8=H ~ 25=Y 7=G
7) 11.09.1969 Mailed letter Values 10=J 1=A ~ 26=Z 8=H
8) 12. 20.1969 Mailed Letter %Values 3=C ~ 20=T 2=B
9) 04.20.1970 Mailed letter ** Values 23=W 5=E ` ~ 13 =M 4=D
10) 04.28.1970 Mailed Letter *# Values 4=D ~ 21=U 3=C
11) 06.26.1970 Mailed Letter *# Values 4=D ~ 21=U 3=C
12) 07.24.1970 Mailed Letter Values 3=C ~ 20=T 2=B
13) 07.26.1970 Mailed Letter Values 5=E ~ 22=V 6=F
14) 10.05.1970 Mailed Letter ** Values 23=W 5=E ~ 13=M 4=D
15) 10.27.1970 Mailed Letter Values 9=I ~ 17=Q 8=H
16) 03,13,1971 Mailed Letter *** Values 25=Y 7=G ~ 15=O 6=F
17) 03 22 1971 Mailed Letter *** Values 25=Y 7=G ~ 15=O 6=F
18) 01.29.1974 Mailed Letter Values 4 =F ~ 23 =W 5=E
19) 02.14.1974 Mailed Letter $Values10=J 1=A ~ 18=R 9=I
20) 05.08.1974 Mailed Letter Values 7=G ~ 24=X 6=F
21) 07.08.1974 Mailed Letter $$Values 9 =I ~ 26=Z 8=H
22) 04.24.1978 Mailed Letter $$$ Values 8=H ~ 25=Y 7=G
Note:
8 pairs (17 dates of 27) are paired (8 sets total)(one set contains 3 matches) WAY BEYOND COINCIDENCE
* = 1st set: A) + 1) both =l 26=Z 8=H ..~ 16=P.. 7=G
% = 2nd set: 2) + 5) + 8) all three = 3=C ~ 20=T 2=B
$$ = 3rd set C) + 21) both = 9=I ~ 26=Z 8=H
$ = 4th set E) + 19) both = 10=J 1=A ~ 18=R 9=I
$$$= 5th set 6) + 22) both = 8=H ~ 25=Y 7=G
** = 6th set 9) + 14) both = 23=W 5=E ` ~ 13 =M 4=D
*** = 7th set 16) + 17) both = 25=Y 7=G ~ 15=O 6=F
*# = 6th set 10) + 11) both = 4=D ~ 21=U 3=C
3 sets are back to back
*( A) 1) ), + *# ( 10) 11) ), + *** ( 14) 17) )
Since Zodiac was (maybe still is?) into pairs and symetry, I decided to use the 2 digit,2 digit,4 digit date and the same date as a 2 didgit,2didgit,2 didgit date (2 conversions to numbers and letters of the alphabet) Example:
02.14.1974 (2 digit,2 digit,4 digit =) 2+1+4+1+9+7+4= 28. since 28 is higher than 26(possible letter count of the alphabet) I broke it again to get 2+8=10. This became the letter J and since 10 breaks again, it gets a second number of 1+0=1 or A,thus in the 2-2-4 digit sequence, this date gets the letters A(1) and J(10) applied to that date. then 02.14.74 (2 digit, 2 digit, 2 digit) gets converted as well in an alternate conversion(2-2-2 didgit sequence) that is 2+1+4+7+4= 18 or 1+8=9 R(18) and I (9)
taking all of the dates I came up with 22 hidden letters of 26 of the alphabet in 27 documented dates. I believe this is something big.
What it means is this:
There is a date or two missing, I suspect it is 2 dates to make the #'s that convert to crime dates that ,with all of the letters, made up the full alphabet and thus, are probably in some way(if the whole alphabet is complete) linked to the way the unsolved cyphers can be interpreted. I know it was a long shot, but now it can be recorded and used. I wonder if anyone ever took the time to do this?
I am missing the converted values of 3 alphabetic letters. The letters are L,N, and V. This means I need to find the crime that was not concidered to be Zodiacs that really is his crime, or the possible 2 crimes I should say. This will be my next task, to find the missing crime(s) date(s) that completes this alphabet. It may also be the 1981 letter, but I havent found it yet. It could also be an earlier nightstalker crime or possibly one of the crimes where he left a match(reference to pairs).
Also I suspect a hidden Baconian cypher and will work it next and explain it as well. for now, here are my results:
Without showing all of the math(since it would take a while to post it all), I gave an example so you can test my conversions, but I simplified it here for you and just gave the final numer and letter value of each date: Do you notice all the pairs and similar results that were found? Only a mathmatician could have calcilated these dates to match like that. This is no coincidence, it was calculated. (MHO)
Crimes are marked with a letter and mailed letters are assigned by number and iin order. I put the crime dates and letters together. Here they are
The digit sequence results of each date is as such as presented. The 2-2-4 sequence results(shown first) and a dash dividing the 2-2-2 sequence (which is shown second).
Example using first Date:
A) 10. 30 1966 / 10.30.66
1+3+1+9+6+6/ or 1+3+6+6
=26 or (2+6=8)/ =16 or (1+6=7)
26 =(Z) 8= (H)/ ~ 16 =P 7 =G
A) 10.30.1966 CRIME Cherri Jo Bates .....*.Values:26=Z 8=H ..~ 16=P.. 7=G
1) 11-29-1966 Mailed Letter *Values 26=Z 8=H ~ 16-P 7=G
2) 04.30.1967 Mailed Letter %Values 3=C ~ 20=T 2=B
B) 12.20.1968 Crime David F and Betty Lou J 11= K ~ 19=S 10=J 1=A
3) 04.31.1969 Mailed Letter Values 6 =G ~ 26=Z 8=H
C) )7.)4.1969 Crime Darlene Ferrin Mike Mageau $$Values 9=I ~ 26=Z 8=H
4) 08.04.1966 Mailed Letter Values 8=H ~ 24=X 6=F
D) 09.27.69 Crime Bryan Hartnell Cecilia Shepard Values 7=G ~ 6=F
E) 10.11.1969 Crime Paul Stine $Values 10=J 1=A ~ 18=R 9=I
5) 10.13.1969 Mailed Letter %Values 3=C ~ 20 =T 2=B
6) Mailed Letter $$$Values 8=H ~ 25=Y 7=G
7) 11.09.1969 Mailed letter Values 10=J 1=A ~ 26=Z 8=H
8) 12. 20.1969 Mailed Letter %Values 3=C ~ 20=T 2=B
9) 04.20.1970 Mailed letter ** Values 23=W 5=E ` ~ 13 =M 4=D
10) 04.28.1970 Mailed Letter *# Values 4=D ~ 21=U 3=C
11) 06.26.1970 Mailed Letter *# Values 4=D ~ 21=U 3=C
12) 07.24.1970 Mailed Letter Values 3=C ~ 20=T 2=B
13) 07.26.1970 Mailed Letter Values 5=E ~ 22=V 6=F
14) 10.05.1970 Mailed Letter ** Values 23=W 5=E ~ 13=M 4=D
15) 10.27.1970 Mailed Letter Values 9=I ~ 17=Q 8=H
16) 03,13,1971 Mailed Letter *** Values 25=Y 7=G ~ 15=O 6=F
17) 03 22 1971 Mailed Letter *** Values 25=Y 7=G ~ 15=O 6=F
18) 01.29.1974 Mailed Letter Values 4 =F ~ 23 =W 5=E
19) 02.14.1974 Mailed Letter $Values10=J 1=A ~ 18=R 9=I
20) 05.08.1974 Mailed Letter Values 7=G ~ 24=X 6=F
21) 07.08.1974 Mailed Letter $$Values 9 =I ~ 26=Z 8=H
22) 04.24.1978 Mailed Letter $$$ Values 8=H ~ 25=Y 7=G
Note:
8 pairs (17 dates of 27) are paired (8 sets total)(one set contains 3 matches) WAY BEYOND COINCIDENCE
* = 1st set: A) + 1) both =l 26=Z 8=H ..~ 16=P.. 7=G
% = 2nd set: 2) + 5) + 8) all three = 3=C ~ 20=T 2=B
$$ = 3rd set C) + 21) both = 9=I ~ 26=Z 8=H
$ = 4th set E) + 19) both = 10=J 1=A ~ 18=R 9=I
$$$= 5th set 6) + 22) both = 8=H ~ 25=Y 7=G
** = 6th set 9) + 14) both = 23=W 5=E ` ~ 13 =M 4=D
*** = 7th set 16) + 17) both = 25=Y 7=G ~ 15=O 6=F
*# = 6th set 10) + 11) both = 4=D ~ 21=U 3=C
3 sets are back to back
*( A) 1) ), + *# ( 10) 11) ), + *** ( 14) 17) )